J.R. S. answered 07/09/20
Ph.D. University Professor with 10+ years Tutoring Experience
First, write the correctly balanced equation for the reaction taking place:
NaHCO3(aq) + CH3COOH(aq) ==>CH3COONa(aq) + H2CO3(aq) ==> CO2(g) + H2O(l) + CH3COONa(aq)
Assuming the "residue" referred to is CH3COONa, we have the following relationship:
18.0 g CH3COONa x 1 mol CH3COONa/82.0 g x 1 mol CO2/mol CH3COONa x 44 g CO2/mol = 9.66 g CO2