
Corey G. answered 07/09/20
Computer Engineering instructor who tutors code, math, and writing.
There are two possible cases here: (1) equally weighted grades or (2) proportionally weighted grades
Case 1: Equally weighted grades
If we assume that all 4 of the tests are equally weighted then,the following inequality needs to be true in order to receive 80 percent (0.80) or greater as an average, where x is the grade on test # 4, out of 200pts.
- (83/100 + 71/100 +74/100 + x/200) / 4 >= 0.80 .... average of 4 equally weighted grades should be at least 80 percent
- (83/100 + 71/100 +74/100 + x/200) >= 3.20 .... multiplying both sides by 4
- 83 + 71 + 74 + x/2 >= 320 .... multiplying both sides by 100
- x/2 >= 320 - 83 - 71 - 74 ..... combining all constant expressions on the right hand side
- x/2 >= 92 .... multiplying both sides by 2
- x > =184 ... so at least 184 out of 200 pts is needed to get a B grade
Case 2: Proportionally weighted grades
On the other hand, if each test is weighted according to the number of points it is out of, then the following inequality has to be solved.
- (83 + 71 + 74 + x)/(100 +100 + 100 +200) >= 0.80 ... Total points earn divided by the total points offered should be at least 80 percent
- (228 + x)/500 >= 0.80 ... combining all constant terms in numerator and denominator
- (228 + x) >= 400 ... multiplying both sides by 400
- x >= 172 .... so at least 172 out of 200 pts is needed to get a B grade