Stoichiometry Question

Question

How many moles of ammonia (NH₃) can be produced from 2.85 grams of nitrogen gas according to the following reaction?

N_2(g)  + 3H_2(g)  --> 2NH_3(g)

Answer 1

N_2(g)  + 3H_2(g)  --> 2NH_3(g) ... balanced equation

Assuming that H₂(g) is NOT limiting, we have the following relationship:

2.85 g N₂ x 1 mol N₂/28 g x 2 mol NH₃/mol N₂ = 0.204 moles NH₃ produced from 2.85 g of N₂