To assume normality n*p > 10 and n(1-p) > 10, where n = 20 and p = 0.81.
n*p = 16.2
n*(1-p) = 3.8
So distribution is NOT approximately normal.
Ariel G.
asked 07/02/20Decide whether or not the following sampling distribution is approximately normal. Explain.
A survey of U.S. adults found that 81% are happy with their current employer. You randomly select 20 adults and ask them if they are happy with their current employer.
To assume normality n*p > 10 and n(1-p) > 10, where n = 20 and p = 0.81.
n*p = 16.2
n*(1-p) = 3.8
So distribution is NOT approximately normal.
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