sample size = (z-critical * standard deviation/margin of error), where z-critical is z-score corresponding to P(z < 0.99).
= (2.33 * 5/0.5)^2 =~ 543
Olivia K.
asked 07/01/20A researcher studying the lifespan of a certain species of bacteria. A preliminary sample of 30 bacteria reveals a sample mean of ¯x=70 hours with a standard deviation of s=5 hours. He would like to estimate the mean lifespan for this species of bacteria to within a margin of error of 0.5 hours at a 98% level of confidence.What sample size should you gather to achieve a 0.5 hour margin of error?He would need to sample ______ bacteria.
sample size = (z-critical * standard deviation/margin of error), where z-critical is z-score corresponding to P(z < 0.99).
= (2.33 * 5/0.5)^2 =~ 543
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