Let n = 36, μ = 19.3, σ = 10.7, and z = 1.96 (since the confident level is 95%).
We will set up the confidence interval for the true population mean.
[19.3 ± 1.96*(10.7/√36)] = [15.8 , 22.8]
We are 95% confident that the true population mean is between 15.8 and 22.8.
Olivia K.
This answer was incorrect. Is there another way to do this problem? I understood your explanation and it should be right but it was counted incorrect. I am trying to learn this type of problem before the test.07/02/20