z = (sample mean - population mean)/(standard deviation/sqrt(sample size)
Need to find z-value such that P(z < z-value) is 0.09.
From standard normal probability table that z value is -1.34.
population mean is 12.5, population standard deviation is 2.4, sample size is 3.
-1.34 = (sample mean - 12.5)/(2.4/sqrt(3))
solve equation for sample mean.