c)
P(x < 240)
Transform to z score = (sample mean - population mean)/(standard deviation(std)/sample size^0.5)
P(z < (240-250)/(50/49^0.5)
P(z < -1.4) = 0.0808
Since probability is > 0.05 this is not an unusual value to obtain by chance.
Ariel G.
asked 06/25/20Suppose the average distance of fly balls hit to the outfield (in baseball) is normally distributed with a mean of 250 feet and a standard deviation of 50 feet. We randomly sample 49 fly balls. Let 𝑋~(𝜇𝑥̅ , 𝜎𝑥̅ ) where 𝑋 = the average distance for 49 fly balls.
c) (i) Compute 𝑃(𝑋 < 240).
(ii) Draw a sketch to interpret your results.
(iii) Is this usual? Explain.
c)
P(x < 240)
Transform to z score = (sample mean - population mean)/(standard deviation(std)/sample size^0.5)
P(z < (240-250)/(50/49^0.5)
P(z < -1.4) = 0.0808
Since probability is > 0.05 this is not an unusual value to obtain by chance.
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