How much heat is required to change 235 g of iodine at 25 degrees C into vapor at 198 degrees C? (The melting point is 113.5 degrees C, and the boiling point is 185.4 degrees C.

Question

Please don't use mol in the explanation. Thank you!

Answer 1

You will need the specific heat of Iodine as well as the ∆Hfusion, ∆Hvaporization, specific heat of Iodine liquid and vapor.

q = mC∆T = (235 g)(Csolid)(88.5 deg) = q1

q = m∆Hfusion = (235 g)(∆Hfuison) = q2

q = mC∆T = (235 g)(Cliquid)(71.9 degrees) = q3

q = m∆Hvap = (235 g)(∆Hvap) = q4

q = mC∆T = (235 g)(Cvapor)(12.6 degrees) = q5

Add up q1 thru q5 to get total heat required.