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Question

A jar contains 8 red marbles numbered 1 to 8 and 6 blue marbles numbered 1 to 6. A marble is drawn at random from the jar. Find the probability of the given event.

(a) The marble is red 

Your answer is :    

(b) The marble is odd-numbered 

Your answer is :    

(c) The marble is red or odd-numbered 

Your answer is :    

(d) The marble is blue or even-numbered 

Your answer is : 

Answer 1

There are a total of 14 marbles.

Let RED = red marble, BLUE = blue marble, ODD = odd number, and EVEN = even number.

P(RED) = 8/14 = 4/7 = 0.5714

P(ODD) = 7/14 = 1/2 = 0.5

P(RED ∪ ODD) = P(RED) + P(ODD) - P(RED ∩ ODD) = 8/14 + 7/14 - 4/14 = 11/14 = 0.7857

P(BLUE ∪ EVEN) = P(BLUE) + P(EVEN) - P(BLUE ∩ EVEN) = 6/14 + 7/14 - 3/14 = 10/14 = 0.7143

Answer 2

The marble is blue and even numbered like this-RR BB RR BB RR BB RR,where 'R' is indicating red marbles and 'B' is indicating blue marble.