For a sample mean P, z-score = (P - population mean)/(standard deviation/square root of sample size).
First find the z-score associated with the 83rd percentile (look up z-score corresponding to 0.83 probability), which 0.954.
Using given population mean (85), standard deviation (33.8), sample size (25) and computed z-score (0.954), you can plug those values into the z-score equation and solve for the associated sample mean P:
0.954 = (P - 85)/(33.8/sqrt(25))
0.954 = (P - 85)/6.76
6.45 = P - 85
P = 91.45 ~ 91.5