Megan W.
asked • 06/23/20Suppose that the useful life of a particular car battery, measured in months, decays with parameter 0.025. We are interested in the life of the battery
. Suppose that the useful life of a particular car battery, measured in months, decays with parameter 0.025. We are interested in the life of the battery.
Given
(a)Find the mean of the random variable. Interpret the results.
(b)Find the probability that a car battery lasts longer than 60 months (5 years).
(c) Find the probability that the car battery last less than 2 years.
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1 Expert Answer
Tom K. answered • 06/23/20
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a) 1/.025 = 40
b) e^-(.025*60) = e^-1.5 = .2231
c)1 - e^-(0.025*2*12) = 1 - e^-.6 = .4512
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Jeremiah T.
It looks to me like there's not enough information to answer these questions. Do you have the mean and standard deviation for the life of the car batteries? Then b and c could be answered06/23/20