Step 2 has a flaw. It assumes that AB and BC are parallel and AC is a straight line. AB and BC can be congruent (same length) and share point B without both points A and C being on the same line as B.
Seirra K.
asked 06/20/20Proof I need Help With question Now Please
Which step in the proof has a flaw?
Given AB¯≅BC¯, prove B is the midpoint of
AC¯
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Step 1
Step 2
No Flaw.
Step 3
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