An unknown gas occupies 85 L of volume at 987 mmHg and 45 ̊C. If the pressure changes to 4 atm and the new temperature is 318 K, what would be the new volume?

Answer 1

Use the ideal gas law: P₁V₁/T₁ = P₂V₂/T₂ Where X₁ and X₂ are the old and new parameters respectively.

[Here, X is P,V, and T]

Solving for the new volume, You get V₂ = P₁V₁T₂/(T₁P₂) ------------------------------------------- (1)

Converting the units give

T₁ = 45^oC = 45+273.15 = 318.15K

T₂ = 318K

P₁ = 987mmHg

P₂ = 4atm = 3040mmHg

V₁ = 85L

Plug these values into the equation above and you get the new volume of the unknown gas to be

V₂ = 27.6 L.