Binomial distribution

Question

About 5% of the population has a particular genetic mutation 900 people are randomly selected find the mean for the number of people with the genetic mutation in such groups of 900

Answer 1

n = 900 people

p = 0.05 of people with genetic mutation

E(X) = np = (900)*(0.05) = 45

We will expect 45 people to have genetic mutation.