how many moles of silver iodide will be produced from 229 g of calcium iodide?

Question

For the chemical reaction

CaI2 + 2AgNO3⟶ 2AgI+ Ca(NO3)2

how many moles of silver iodide will be produced from 229 g of calcium iodide?

Answer 1

mass of reactant --- moles of reactant --- stoichiometric relation --- moles of product --- mass of product

Assuming excess AgNO₃.

CaI₂ :

Molar mass: (40+126.9 x 2) = 293.8 g/mol

moles of CaI₂ = 229 g / 293.8 g/mol = 0.779 mol

According to the equation, for every mole of CaI₂ two moles of AgI is produced.

So this reaction produces : 2 x 0.779 mol = 1.56 mol (take S.F. = 3)

Molar mass of AgI = 169.9 + 126.9 = 296.8 g/mol

Mass of AgI = 1.56 mol x 296.8 g/mol = 463 g.// answer

HIH!

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