How many molecules (not moles) of NH3 are produced from 1.59*10^-4g of H2?

Answer 1

Setup equation first:

N₂ + 3 H₂ <===> 2 NH₃ It is a reversible reaction. Let's assume 1.59 x 10^-4 g of hydrogen is consumed.

mass --- moles --- stoichiometric ratio --- moles --- # of particles (involving the Avogadro #: 6.02 x 10²³)

1.59 x 10^-4 g / 2g/mol = 7.95 x 10^-5 mole

For every 3 mol of H_2, 2 mol of NH₃ is produced, so we have:

(7.95 x 10^-5 mol)/3 x 2 = 5.3 x 10^-5 mol of NH₃ is produced.

1 mol = 6.02 x 10²³ so,

5.3 x 10^-5 x 6.02 x 10²³ = 3.19 x 10¹⁹ molecules of ammonia, NH_3. // answer.

Chemist can count molecules !!!