Binomial distribution is applicable here. Probability at least one will have a defect = 1 - probability (none will have a defect) = 1 - C(7,0) (0.03)^0 (0.97)^7 = 1 - 0.808 = 0.192.
Ariel G.
asked • 06/16/20A manufacturing machine has a 3% defect rate. If 7 items are chosen at random, what is the probability that at least one will have a defect?
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