J.R. S. answered 06/15/20
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q = mC∆T
q = heat = ?
m = mass = 74 g
C = specific heat of water = 4.184 J/gº
∆T = change in temperature = 63º - 31º = 32º
Solving for q:
q = (74 g)(4.184 J/gº)(32º)
q = 9908 J = 9900 J = 9.9 kJ