F = football player
B = basketball player
P(F) = 0.5
P(B) = 0.21
P(F and B) = 0.15
P(F or B) = P(F) + P(B) - P(F and B) = 0.5 + 0.21 - 0.15 = 0.56
Ariel G.
asked 06/14/20A survey of athletes at a high school is conducted, and the following facts are discovered: 50% of the athletes are football players, 21% are basketball players, and 15% of the athletes play both football and basketball. An athlete is chosen at random from the high school: what is the probability that they are either a football player or a basketball player?
F = football player
B = basketball player
P(F) = 0.5
P(B) = 0.21
P(F and B) = 0.15
P(F or B) = P(F) + P(B) - P(F and B) = 0.5 + 0.21 - 0.15 = 0.56
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