Tom K. answered 06/14/20
Knowledgeable and Friendly Math and Statistics Tutor
As we talk of the distribution having mean ß, clearly, our method of moments estimator is simply the sample mean. We could calculate the mean by calculating I[0, ∞) x/ß e-x/ß dx, but that would simply return ß. The MOM estimator of ß is ∑xi /n = x-bar
Now, to the MLE estimator, maximize the log-likelihood. The log likelihood equals - ln ß - x1/ß - lnß - x2/ß - .... - ln ß - xn/ß = -n ln ß - 1/ß∑xi
We take the derivative and set it equal to 0.
-n/ß + 1/ß2∑xi = 0
1/ß2∑xi = n/ß
Multiply both sides by ß2/n
∑xi /n = ß
The sample mean is also the MLE estimate of ß