An aqueous solution of sucrose (C12H22O11) is prepared by dissolving 6.5532 g in sufficient deionized water to form a 50.00 mL solution. Calculate the molarity of the solution.

Answer 1

Molarity is defined as moles of solute per liter of solution.

The liters of solution is found by converting 50.00 ml to liters: 50.00 ml x 1 L/1000 ml = 0.05000 L

Moles of solute is found by converting grams of sucrose to moles of sucrose using the molar mass:

molar mass C12H22O11 = 342.3 g/mol

6.5532 g x 1 mol/342.3 g = 0.01914 moles

Molarity (M) = 0.01914 moles/0.05000 L = 0.3828 M