The 63% percentile corresponds to a z-score of 0.332. The data value is 0.332 standard deviations above the mean.
Guadalupe M.
asked 06/12/20A data value is in the 63rd prercentile.
a) Find the standard score that corresponds to the data value.
b) State the number of standard deviations that the value lies above or below the mean.
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