What is the amount of solid that each product forms? What is the percent yield? Check description for full question.

Question

3.5 g Calcium acetate reacts with 5.5g sodium hydroxide in a double displacement reaction write a balanced chemical equation. Determine the amount of solid each product that forms. Determine the percent yield if .35 g of the first product forms.

Answer 1

calcium acetate = Ca(CH3COO^-)₂

If we call the acetate anion Ac-, we can write calcium acetate as Ca(Ac)₂

Ca(Ac)₂(aq) + 2NaOH(aq) ==> 2NaAc(aq) + Ca(OH)₂(s)

The only solid that forms is calcium hydroxide, Ca(OH)₂

3.5 g Ca(Ac)₂ x 1 mol Ca(Ac)₂/158.17 g = 0.0221 moles Ca(Ac)₂

moles NaOH = 5.5 g NaOH x 1 mol NaOH/40.0 g = 0.1375 moles NaOH

Ca(Ac)₂ is the LIMITING REACTANT because of the 2:1 mol ration of NaOH:caclcium acetate

Theoretical yield of Ca(OH)₂ = 0.0221 mol Ca(Ac)₂ x 1 mol Ca(OH)₂/mol Ca(Ac)₂ x 74.1 g/mol = 1.54 g

Percent yield = actual/theoretical (x100) = 0.35 g/1.54g (x100%) = 22.7% = 23% yield