Sam Z. answered 06/09/20
Math/Science Tutor
1 gal =231 cu/in
r^2pi*ht=area
36pi*7= 791.68cu/in
231*3.25=750cu/in
41.68/(r^2pi)
=41.65/113.1=.368"
Maria A.
asked 06/09/20How far from the top of the punch bowl is the top of the punch?
Sam Z. answered 06/09/20
Math/Science Tutor
1 gal =231 cu/in
r^2pi*ht=area
36pi*7= 791.68cu/in
231*3.25=750cu/in
41.68/(r^2pi)
=41.65/113.1=.368"
Note that 1 gallon = 231 cubic inches.
Volume of liquid = 231 cubic inches = PI*R^2*H (equation for volume of a cylinder)
We have radius (half diameter), so we can figure out the height of the liquid.
To figure how far below the top the liquid is, we subtract the height of the liquid from the height of the punch bowl (7 inches).
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