6 need help please

Question

How many grams of Kr are in a 1.55 L cylinder at 52.8 ∘C and 9.07 atm?

Answer 1

PV = nRT

Solve for n (moles) and then convert to grams.

n = PV/RT = (9.07 atm)(1.55 L)/(0.0821 Latm/Kmol)(325.95

n = 0.525 moles of Kr

grams Kr = 0.525 moles x 83.8 g/mol = 43.7 g (3 sig. figs.)