J.R. S. answered 06/08/20
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pOH = - log [OH-] = 6.92
pH = 14 - pOH
pH = 7.08 (answer b)
Zuhra A.
asked 06/08/20A solution in which [OH^-] = 1.20*10^-7 M has a PH of
a)6.92
b)7.08
c)5.35
d)8.75
J.R. S. answered 06/08/20
Ph.D. University Professor with 10+ years Tutoring Experience
pOH = - log [OH-] = 6.92
pH = 14 - pOH
pH = 7.08 (answer b)
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