Help With Basic Chem

Question

How much heat energy is required to boil 76.0 g of ammonia, NH3? The molar heat of vaporization of ammonia is 23.4 kJ/mol.

𝑞= kJ

Answer 1

If the temperature of the ammonia is already at the boiling point, and you are only asking how much heat is needed to vaporize the ammonia, then the answer is as follows:

76.0 g NH₃ x 1 mol NH₃/17 g x 23.4 kJ/mol = 104.6 kJ = 105 kJ

If you are asking how much heat is needed to bring the temperature of the NH₃ to the boiling point, then we cannot answer this unless we know the initial temperature of the NH₃ and the specific heat of NH₃.