J.R. S. answered 06/02/20
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41.45 g x 0.148 kJ/g x 1000 J/kJ = 6134.6 J = 6130 J (3 sig. figs. based on 0.148 kJ/g)
Anna M.
asked 06/01/20The heat of fusion for naphthalene is 0.148kJ/g. Calculate the heat energy in joules required to melt 41.45 g of naphthalene.
Heat Energy: J
J.R. S. answered 06/02/20
Ph.D. University Professor with 10+ years Tutoring Experience
41.45 g x 0.148 kJ/g x 1000 J/kJ = 6134.6 J = 6130 J (3 sig. figs. based on 0.148 kJ/g)
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