What is the Radius of the following circle: x^2 - 6x + y^2 - 4y + 3 = 0

Answer 1

Steps:

1. Rewrite the equation in the standard form: (x – h)² + (y – k)² = r²
2. You can rewrite this equation by trying to group the "x" and the "y" separately.
3. Move the constant to the right side of the equation
4. Use the complete the square method for both "x" and "y"
5. Write the left side in the form of two squared binomials and simplify the result on the right side
6. You can square root the number presented on the left side of the equation
7. The center will be (h, k) and the radius=r

If you follow these steps accurately, you should find center (3,2) and radius= 4

I hope I was a help! Let me know if you have any questions!