25.0 grams of chlorine reacts with 29.0 grams of sodium 2Na+Cl2→2NaCl The theoretical yield is _____

Answer 1

Looking at the balanced equation

2Na + Cl₂ ==> 2NaCl

we see 2 moles Na reacts with 1 mole Cl₂ to produce 2 moles of NaCl

Since we are given grams of Na and grams of Cl₂, we need to first convert all to moles

25.0 g Cl₂ x 1 mol Cl2/70.9 g = 0.353 moles Cl₂

29.0 g Na x 1 mol Na/22.99 g = 1.26 mol Na

According to the balanced equation, which one is in limiting supply?

It would be the Cl₂ because of the mole ratio of 2:1 for Na : Cl₂

Theoretical yield will thus be based on amount of Cl₂ :

0.353 moles Cl₂ x 2 moles NaCl/mole Cl₂ = 0.706 moles NaCl formed

mass NaCl = 0.706 moles NaCl x 58.44 g/mol = 41.3 g NaCl theoretical yield