In Geometry, it is a given that the perimeter of a rectangle is the sum of the length of all sides. Therefore we can say that the Perimeter (P) is equal to 2xLength (L) + 2xWidth (W)
So, P = 2L + 2W
Now what?
Well, we know that the Length of the rectangle is 3 yards longer than its Width. Therefore, L = W + 3.
Now we can subsitute this into the perimeter equation in order to have only W's in there.
P = 2(W+3) + 2W
Let's simplify:
P = 2W + 2x3 + 2W
P = 2W + 6 + 2W
P = 4W + 6
We can add the two W's since they are the same variable.
Now, knowing that P = 62 yards, we cal plug this into the equation to solve for W, since it will be the only remaining variable.
62 = 4W + 6
Now we just have to solve for W using simple arithmetic.
62 - 6 = 4W
56 = 4W
56/4 = W
14 = W
Now we know that the Width is 14 yards, we can use this information to solve for the Length, because we know that the Length is 3 yards longer than the Width. This ties back to earlier in the problem.
L = W + 3
Now substituting in the actual value of W and solving for L:
L = 14 + 3
L = 17
Therefore, the Width is 14 yards and the Length is 17 yards!
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