
Christopher J. answered 05/28/20
Berkeley Grad Math Tutor (algebra to calculus)
Luhan:
Use radians instead of degrees. You need to change f(x) =55 to f(x) =60
degrees radians f(x)
0 0 60
15 π/12 35
30 π/6 10
45 π/4 35
60 π/3 60
75 5π/12 35
90 π/2 10
105 7π/12 35
120 2π/3 60
We can write the equation in the form f(x) = A*cos(ω(x-B))+C
A (amplitude) = (60-10)/2 = 25
period = 2π/ω The period is π/3 since f(0) = 60 f(π/3) =60 f(2π/3) =60
solving for ω, ω = 6
There is no horizontal offset. The graph reaches a maximum value at x=0 just like the standard cos() function.
C = (60+10)/2 = 35
We get f(x) = 25*cos(6x) + 35
I'll let you do the sin() function; There will be an offset of π/12 so B = π/12 for the sin()
Luhan E.
is it 25 sin 6(pi/12)+3505/29/20

Christopher J.
try 25*sin(6(x+(π/12)))+35 plug in numbers05/29/20
Luhan E.
it doesn't work I plugged in 0 and I got 14 not 6005/29/20
Luhan E.
should the 35's be changed in the table05/29/20

Christopher J.
25*sin(6*(0+π/12))+35 = 25*sin(6(π/12)) + 35 = 25*sin((π/2))+35 = 25*1+35 =6005/29/20

Christopher J.
sin(pi/2) = 1. Make sure you are in radian mode if you are using your calculator.05/29/20
Luhan E.
What I got for the sin function is 25 sin(6x)+ 35, is this correct05/28/20