C3H8 + 5O2 --> 4H2O + 3CO2 If 200. g of propane is burned, how many g of H2O are produced?

Answer 1

Once again...

C₃H₈ + 5O₂ ==> 4H₂O + 3CO₂ ... balanced equation

Using stoichiometry from the balanced equation and dimensional analysis, we find the mass of H₂O:

200.g C₃H₈ x 1 mol C₃H₈/44.1 g x 4 mol H₂O/1 mol C₃H₈ x 18.0 g H₂O/mol = 327 g H2O (3 sig. figs.)

If you don't understand this problem, write a comment and maybe I can answer it better.

Answer 2

C₃H₈ + 5O₂ ==> 4H₂O + 3CO₂ ... balanced equation

Using stoichiometry from the balanced equation and dimensional analysis, we find the mass of H₂O:

200.g C₃H₈ x 1 mol C₃H₈/44.1 g x 4 mol H₂O/1 mol C₃H₈ x 18.0 g H₂O/mol = 327 g H2O (3 sig. figs.)