J.R. S. answered 05/26/20
Ph.D. University Professor with 10+ years Tutoring Experience
It seems as though I am doing all of your homework for you. So, in this problem, I'll get you started and hopefully you can complete the assignment.
Always start with the balanced equation:
2H2 + O2 ==> 2H2O ... balanced equation
Anytime you are given amounts of BOTH reactants, you MUST find the limiting reactant:
10.9 g H2 x 1 mol H2/2 g H2 = 5.45 mol H2
16.03 g O2 x 1 mol O2/32 g O2 = 0.500 mol O2
Clearly, by looking at the balanced equation you can tell that O2 is limiting because it takes 2 mol H2 for each 1 mol O2, and there is plenty of H2 present (5.45 mol vs. 0.500 mol).
Now you can find maximum amount H2O formed:
0.500 mol O2 x 2 mol H2O / 1 mol O2 x 18 g H2O/mol H2O = answer in grams