
Christopher J. answered 05/26/20
Berkeley Grad Math Tutor (algebra to calculus)
Becky:
Let C (x,y) be the center of the circle.
Since Q, R, S are all suppose to lie on the circle, distances CQ, CR, an CS are all equal (they are all radii so to speak).
Using the distance formula,
d(CS) = √((x-0)2 +(y-2)2)
d(CR) = √((x-2)2+(y+4)2)
d(CQ) = √((x-4)2+ (y+2)2)
We solve d(CS) = d(CR) and d(CR) =d(CQ)
1) d(CS) = d(CR)
√(x2+(y-2)2) = √((x-2)2+(y+4)2)
x2+(y-2)2 = (x-2)2 + (y+4)2
x2+(y2-4y+4) = (x2-4x+4) + (y2+8y+16)
4x-12y = 16
2) d(CR) = d(CQ)
√((x-2)2+(y+4)2) = √((x-4)2+ (y+2)2)
(x-2)2+(y+4)2 = (x-4)2+ (y+2)2
x2-4x+4 + y2+8y+16 = x2-8x+16 + y2+4y +4
4x+4y =0
You need to solve the system of equations for x and y
4x+4y = 0
4x-12y = 16
I'll let you figure out the last part. Let me know if you need any other help!