Please help as soon as possible pretty please!

Question

Question 1: Identify the value of x.



A.) x = 24

B.) x = 8

C.) x = 12

D.) x = 7

Question 2: Identify the equation of the circle B that passes through (4,−6) and has center (3,−2).

A.) (x − 3)² + ( y + 2)² = 17

B.) (x + 3)² + ( y − 2)² = 17

C.) (x + 3)²+(y − 2)² = √17

D.) (x − 3)²+(y + 2)² = √17

Please give explanations and answer.

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Answer 1

Becky:

Question 1)

PQ² = QR*QS remember QS = 4+12=16

Question 2)

We know (x-3)²+(y+2)²=d²

d is equal to the distance between a point on the circle and the circle center. In other words, d is equal to

the distance (4,-6) and (3,-2)

Answer 2

The answer for #1 is x=8. The formula = the tangent squared is equal to the product of the full secant multiplied by the external part of the secant. Therefore, x squared = 16x4, then x squared = 64, then x=8.

The answer for #2 is A.This is because you first reverse the sign of the center of the circle. So (3,-2) fits with (x-3) and (x+2), as shown in answer A. However, the formula for the equation of the circle is x squared + y squared = r squared, where r is the radius. So we need to show (x-3) squared + (x+2) squared. The radius is found by using the distance formula from the point on the circle to the center. Therefore, the square root of (-6- -2)squared + (4-3)squared gives us the square root of (-4) squared + (1) squared = the square root of 17 squared, or 17. This gives us the answer A.