How much heat is released when 30 g of water at 96°C cools to 25°C? The specific heat of water is 4.18 J/g°C.

Question

How much heat is released when 30 g of water at 96°C cools to 25°C? The specific heat of water is 4.18 J/g°C. 

Answer 1

q = mC∆T

q = heat = ?

m = mass = 30 g

C = specific heat water = 4.18 J/gºC

∆T = change in temperature = 96º - 25º = 71ºC

q = (30 g)(4.18 J/gºC)(71ºC)

q = 8903 J of heat released during cooling process (the sign would be negative since heat is released)