J.R. S. answered 05/22/20
Ph.D. University Professor with 10+ years Tutoring Experience
I got the following:
1.012x10-3 J / (0.025456g)(0.0115K) = 3.46 J/g/degree K (to 3 significant figures)
The three sig. figs. is based on only 3 s.f. in temperature value 0.0115 K