J.R. S. answered 05/21/20
Ph.D. University Professor with 10+ years Tutoring Experience
PCl5(g) <==> PCl3(g) + Cl2(g) 𝐾c=1.80 at 250ºC
Convert PCl5 to a molar concentration and then use an ICE table.
[PCl5] = 0.2936 mol/4.20 L = 0.06990 M
Set up an ICE table:
PCl5(g) <==> PCl3(g) + Cl2(g)
0.06990..........0.............0........Initial
-x...................+x...........+x.......Change
0.0699 -x........x.............x........Equilibrium
Write the equilibrium expression:
Kc = [PCl3][Cl2] / [PCl5] .180
1.80 = (x)(x) / (0.6990 - x)
Solve for x using quadratic equaiton:
0.1258 - 1.80x - x2 = 0
x = 0.06737
Equilibrium concentrations:
[PCl5] = 0.06990 - 0.06737 = 0.002530 M
[PCl3] = 0.06737 M
[Cl2] = 0.06737 M