What is the new volume if 60.0 mL of gas is cooled from 33.0°C to 5.00°C?

Answer 1

Like your other questions, you can use a form of the combined gas law. In this case it will be

V1/T1 = V2/T2

V1 = 60.0 ml

T1 = 33 + 273 = 306K

V2 = ?

T2 = 5 + 273 = 278

NOTE: Temperature must always be in Kelvin

Plug in and solve for V2