Oxygen gas is at a temperature of 40°C when it occupies a volume of 2.3 L. To what temperature should it be raised to occupy a volume of 6.5 L?

Answer 1

Initial temperature = T1 = 40C + 273 = 313K

Initial volume = V1 = 2.3 L

Final temperature = T2 = ?

Final volume = V2 = 6.5 L

Assuming constant pressure, we have Charles' Law: V1/T1 = V2/T2

2.3 L/313K = 6.5 L/T2

T2 = 885 K