Tom K. answered 05/19/20
Knowledgeable and Friendly Math and Statistics Tutor
If 50 of 90 fail at 263 minutes, our estimate is that F(263) = 50/90
Then, F(t) = 1 - e-λt ;1 - e-λ(263) = 50/90; e-λ(263) = 40/90
-λ(263) = ln(4/9); λ = ln(9/4)/263
Then, for the 80th failure, λt = -ln(10/90) = ln(9)
t = ln(9)/(ln(9/4)/263) = 263 * 2 ln(3)/(2 ln(3) - 2 ln(2)) = 263 ln(3)/(ln(3)-ln(2) = 263/(1 - ln(2)/ln(3)) = 712.6
If 5% fail, 95% remain. t = 263 ln(20/19)/ln(9/4) = 16.64