Question in the description can you please explain how you got the answer, thank you.

Question

A container of gas at 2.5 atm of pressure occupies 18.0 L of space. It is placed in a freezer where temperature is negative 20 degrees Celsius. The volume of this gas dropped to 8.0 L and the pressure to 2 atm. What was the initial temperature of this gas?

Answer 1

Use the Combined Gas Law:

P1V1/T1 = P2V2/T2

P1 = 2.5 atm

V1 =18.0 L

T1 = ?

P2 = 2 atm

V2 =8.0 L

T2 = -20ºC + 253 = 293K

Plug values in and solve for T1:

T2 = (2.5)(18)(293) / (2)(8)

T2 = 824K