Patrick L. answered 06/29/20
This one will require you to use the chi-square table in order for you to find the confidence interval for variance and standard deviation.
n = 22 students and s2 = 2.6 years
DF (degrees of freedom) = 22 - 1 = 21 and α = 0.10 (10% level of significance)
By using the chi-square table, you should get χ20.05 = 32.671 and χ20.95 = 11.591.
Use the following inequality to find the confidence interval for variance and standard deviation:
[(n - 1)*s2] / χ20.05 ≤ σ2 ≤ [(n - 1)*s2] / χ20.95
[(22 - 1)*(2.6)] / 32.671 ≤ σ2 ≤ [(22 - 1)*(2.6)] / 11.591
1.671 ≤ σ2 ≤ 4.711 (Confidence Interval for Variance)
1.293 ≤ σ ≤ 2.170 (Confidence Interval for Standard Deviation)