J.R. S. answered 05/18/20
Ph.D. University Professor with 10+ years Tutoring Experience
∆Hrxn = ∑[2∆HfHCN(g) + 6∆HfH2O(g)] - [2∆HfNH3(g) + ∆HfCH4(g)]
Look up the values in a table and perform the above calculation. Note that ∆Hf for 3O2(g) is not included as the value is zero.