J.R. S. answered 05/15/20
Ph.D. University Professor with 10+ years Tutoring Experience
BaF2(s) <==> Ba2+(aq) + 2F-(aq)
Ksp = [Ba2+][F-]2
The molar mass of BaF2 = 175.3 g/mol
molar concentration of the saturated solution = 0.048 g x 1 mol/175.3 g = 2.7x10-4 moles/0.015 L = 1.8x10-2 M
[Ba2+] = 1.8x10-2 M
[F-] = 2 x 1.8x10-2 M = 3.6x10-2 M
Ksp = (1.8x10-2)(3.6x10-2)2
Ksp = 2.3x10-5