In ΔSTU, the measure of ∠U=90°, TS = 41, UT = 9, and SU = 40. What is the value of the sine of ∠S to the nearest hundredth?

Answer 1

For this type of question, it's always a good idea to draw and label the given triangle.

Once you do that, you'll be able to see the sin(S) = 9/41 (remember that sinΘ= opposite/hypotenuse)

Divide 9 by 41 and you'll get sin(S) = 0.22