Find the perimeter of the triangle with vertices at​ A(0,0), ​B(-4​,-3​), and ​C(- 6​,0)

Question

The perimeter of the triangle is

Answer 1

For this problem, you need to do the distance formula 3 times. If you sketch the triangle, you can see that you will need to find the distance between AB, AB and AC.

Here is the formula:

d=√(x₂​−x₁​)²+(y₂​−y₁​)²

First, AB (0,0) and (-4,-3)

d=√(-4−0​)²+(-3​−0​)²

d=√(-4​)²+(-3​​)²

d=√16+9

d=√25

d=5

Next, BC (-4,-3) and (0,-6)

d=√(0−(-4​))²+(-6-(-3)​)²

d=√(0+4)²+(-6+3​)²

d=√(4)²+(-3​)²

d=√16+9

d=√25

d=5

For the side AC, you can use the distance formula too. But if you sketch it, you can easily see from the drawing it is 6 units

d=6

For the perimeter, we add all the sides together.

5+5+6 = 16 units

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