How much KI is needed to prepare 750 mL of a 0.250 M solution?

Answer 1

0.250 M KI means 0.250 moles KI/L solution

Since you only need to make 750 ml solution, we perform the following calculation:

750 ml x 1 L/1000 ml = 0.750 L

0.750 L x 0.250 mol/L = 0.1875 moles = 0.19 moles KI needed (this would be the answer in moles).

If you want the answer in grams:

molar mass KI = 166 g/mol

0.1875 moles x 166 g/mol = 31.12 g = 31 g KI needed